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hi max i am trying to achieve use single mixer by giving my local stream name "room1-prateek" and then add it to the mixer but now mixer create "room1-room1-prateek" is it possible to override it by "room1-prateek" or mixer use my stream name "room1-prateek" as it as without my own audio ...

Thank you max for this information You said use roomapi for that but as per my application requirements is roomapi functionally able to add or remove and mute or unmute participant stream at host side? can we do that

i want to use only one mixer where audio dont fallback to me and also see other participant when i removed my stream from the mixer

hey max this seems not reliable if i am switching between this two mixer(1st mixer - "room1" and 2nd mixer - "room1-prateek"(without my own audio) )then there is a some delay is there any alternate way of doing same thing without any delayed & dont playback my audio thanks

right now i am not playing participant stream ,i am just switch the stream between MCU player("room1") and mystream("room1-prateek")

on first run it successfully execute when i hit add host then it play "room1-prateek" (without my own audio) and when i hit remove then it play "room1"(my mixer localstream name)and hit removeMCu button then it remove the "room1" mixer from the div but on second run where i repeat my flow like...

i sent the code please check

i am getting an duplicate div elements when try to stop one stream and playing other stream i attached the problem below

hello max thank you now i am facing issue when i stop the roomname-host and play roomname stream then my div element makes duplicate (makes duplicate when i trigger REST Api stream/terminate or playing stream) i attached my screenshot please look at it ?

thanks max but i have one more query suppose In MCU there are 2 stream are playing ,one is host and other is participant. now,if i remove the localstream from the MCU(for ex : i removed host stream from the MCU), then my stream of MCU that is PLAYING (on my page )is also removed and in this case...

hello max i did the above now i cannot see my MCU //when localstreampublishing i call playStreamfunction like this function startStreaming(session) { var streamName = username; var constraints = { audio : {deviceId : audioid}...

hello max no problem face in MCU_client.html i also set the mixer_auto_start=true mixer_mcu_audio=true mixer_mcu_video=true properties in flasphoner.properties file when my application start, i create the mixer using REST API var roomname = "room1"; var username = "abc"; const options = {...

function participantStream(session) { var streamName = participantname; publishStream = session.createStream({ name: streamName, display: document.getElementById("participantview"), constraints : { audio : {deviceId : paudioid}, video ...

ok Max

thanks max its working but i have a question in utils.js there is function (line number 117) $(function () {.....}) if i have to import this js file and run my code it gives me error utils.js:117 Uncaught ReferenceError: $ is not defined and also gives me TypeError: Cannot read property...

hello when submitting the form i am getting this response Cообщение <1621596295.60a798872a73f@flashphoner.com> для support@flashphoner.com не было доставлено через ApMailer\Smtp. Ошибка: 102: На этапе "Отправление письма" ожидался код 250, но сервер вернул 552 5.7.0 message content and...

sharbtn.onclick = startSharing(); function startSharing() { var session = Flashphoner.getSessions()[0]; var constraints = { video: {} }; constraints.video.type = "screen"; constraints.video.withoutExtension = true; session.createStream({ name:"desktop"...

hey max , i have multiple stream along with add button each and i am using roomAPI(conference part) 1) how i add one stream or both stream on MCU client 2) and also how i manipulate their audio basis on actively speaking

hey max! how can i publish host and participant stream on same page without using roomAPI?

hello max can i publish stream on one page and playback that published stream on another page ,is there any way to do that.